Sin(π/2-θ) 206021-Cos2θ=sin(π/2-2θ) Didi Wahyudi

Sin2(θ)cos2(θ) = 1 (To the real showoffs try R dx sin2(ax) cos2(ax) = − 1 32a sin(4ax) x 8) As the exercise suggests, we first replace the sin...